\newproblem{lay:3_3_3}{
  % Problem identification
	\begin{large}
	  \hspace{\fill}\newline
    \textbf{Lay, 3.3.3}
	\end{large}
	\\
  \ifthenelse{\boolean{identifyAuthor}}{\textit{Laura Zarandieta, Oct. 29th 2013} \\}{}

  % Problem statement
	Use Cramer's rule to solve the following equation system
	\begin{center}
		$3x_1-2x_2=7$\\
		$-5x_1+6x_2=-5$
	\end{center}
}{
   % Solution
	\begin{center}
		$x_1=\frac{\left|\begin{array}{rr} 7 & -2 \\ -5 & 6\end{array}\right|}{\left|\begin{array}{rr} 3 & -2 \\ -5 & 6\end{array}\right|}			 =\frac{7\cdot 6 - (-2)(-5)}{3\cdot 6 - (-2)(-5)}=\frac{32}{8}=\displaystyle{4}$ \\
		$x_2=\frac{\left|\begin{array}{rr} 3 & 7 \\ -5 & -5\end{array}\right|}{\left|\begin{array}{rr} 3 & -2 \\ -5 & 6\end{array}\right|}			 =\frac{3(-5) - 7(-5)}{3\cdot 6 - (-2)(-5)}=\frac{20}{8}=\frac{10}{4}=\displaystyle{2.5}$ \\
	\end{center}
}
\useproblem{lay:3_3_3}
\ifthenelse{\boolean{eachProblemInOnePage}}{\newpage}{}
